Suppose the same magnitude force is applied at the same point as in the example, and the torque is found to have the same magnitude but in the opposite direction of the torque found there. What are the components of the force?

-i - 7j

Explanation:

The computation of components of the force is shown below:-

torque T = r cross F

T = (4.00 i + 5.00 j + 0 k) X (1.00 i + 7.00 j)

Now we will cross multiplying vectorilly

T = 4 × (iXi) + 28 × (jXi) + 0 + 5 × (iXj)35 × (jXj) + 0

T = 4 × 0 + 28 × (-k) + 5 × (k) + 35 × 0

T = 28 × (-k) + 5 × (k) = -23k

net torque |T| = 23 N - m

direction >> negative k

Or Simply we can do by the below method

r × f

28 - 5 = 23 K

-i - 7j

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

i believe the answer is a hope it and is correct