You throw a Frisbee of mass m and radius r so that it is spinning about a horizontal axis perpendicular to the plane of the Frisbee. Ignoring air resistance, the torque exerted about its center of mass by gravity is

following are the response to the given question:

The torque is calculated as the product of the pressure and also the perpendicular distance between both the force and the axis.In this case, gravity acts at the center, as well as the rotational axis likewise passes through it.As a result, the perpendicular distance between both the force and the rotational axis is 0.

Calculating the torque:

Therefore, the final torque would be '0'.

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Ithink d is the right answer. hope this !