Find the buoyant force on a brass block 10.5 cm long by 12.3 cm wide by 15.0 cm high when placed in (a) water, (b) glycerine, and (c) mercury

(a) F = 18.99 N

(b) F = 23.96 N

(c) F = 258.56 N

Explanation:

First we need to find the volume of the block:

Volume of Block = V = (Length)(Width)(Height)

V = (10.5 cm)(12.3 cm)(15 cm)

V = (0.105 m)(0.123 m)(0.15 m)

V = 0.00194 m³

Now, the buoyant force i given by the formula:

F = (Density of Fluid)(V)(g)

(a)

F = (Density of Water)(V)(g)

F = (1000 kg/m³)(0.00194 m³)(9.8 m/s²)

F = 18.99 N

(b)

F = (Density of Glycerine)(V)(g)

F = (1260 kg/m³)(0.00194 m³)(9.8 m/s²)

F = 23.96 N

(c)

F = (Density of Mercury)(V)(g)

F = (13600 kg/m³)(0.00194 m³)(9.8 m/s²)

F = 258.56 N

answer(20) psi;