It is found that, when a dilute gas expands quasistatically from 0.40 to 3.5 L, it does 340 J of work. Assuming that the gas temperature remains constant at 300 K, how many moles of gas are present?

The number of moles of gas present is 0.0629 mol.

Explanation:

Given;

initial volume of the gas, = 0.4 L = 0.4 x 10

final volume of the gas, = 3.5 L

work done by the gas, W = 340 J

constant temperature, T = 300 K

gas constant, R = 8.31 J/mol.K

work done by gas at constant temperature is given as;

Therefore, the number of moles of gas present is 0.0629 mol.

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