Oh football player kicks a football from the height of 4 feet with an initial vertical velocity of 64 ft./s use the vertical motion model H equals -16 tea to the power of 2+ VT plus S where V is initial velocity and feet per second and S is the height and feet to calculate the amount of time the football is in the air before it hits the ground round your answer to the nearest 10th if necessary.

The amount of time the football spent in air before it hits the ground is 4.1 s.

The given parameters;

To find:

Using the vertical model equation given as;

the final height when the ball hits the ground, H = 0

Thus, the amount of time the football spent in air before it hits the ground is 4.1 s.

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4.1 seconds

Explanation:

The height of the football is given by the equation:

Using the inicial position S = 4 and the inicial velocity V = 64, we can find the time when the football hits the ground (H = 0):

Using Bhaskara's formula, we have:

A negative time is not a valid result for this problem, so the amount of time the football is in the air before hitting the ground is 4.1 seconds.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.