At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 65.9 V/m. Find the magnetic field strength B, the total energy density u, and the power flow per unit area, all at the same instant and location.

B = 2.19*10^-7 T

u = 1.92*10^-18 J/m^3

P = (4pi r^2)cεo E^2

Explanation:

In order to find the magnetic field strength of the electromagnetic wave you use the following formula:

    (1)

B: magnitude of the magnetic field

E: magnitude of the electric field = 65.9V/m

c: speed of light = 3*10^8m/s

The magnitude of the magnetic field 2.19*10^-7 T

The energy density of the electromagnetic wave is:

      (2)

εo: dielectric permittivity = 8.85*10^-12C^2/Nm^2

The energy density of the electromagnetic wave is 1.92*10^-8J/m^3

The power is given by:

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is

i don't understand. explain it clearly