Physics
Physics, 01.07.2020 15:01, tyler9158

A thin, hollow tube with cross-sectional area 2 cm2 and length 20 cm has a 22 g mass at the bottom. It is dropped into a volume of water and comes to a rest in a vertical position. a. If you move the bobber up or down, it will experience a force that returns it to its equilibrium position like a spring. What is the effective spring constant (in N/m) created by the weight and buoyant force?
b. What is the natural frequency at which the bobber will bob in rad/s? Answer is 1.95, and 9.88 respectively. Please explain.

answer
Answers: 3

Other questions on the subject: Physics

image
Physics, 22.06.2019 09:30, morgan15776
Acar drives toward the right over the top of a hill, as shown below. which arrow represents the centripetal acceleration? w x y z
Answers: 3
image
Physics, 22.06.2019 12:30, ayoismeisjjjjuan
Cathy is pedaling down a steep hill on her bicycle and wants to be able to coast up the next hill, which is 25 meters high, without pedaling. cathy and her bicycle have a mass of 75 kg. assuming her bicycle is 100% efficient, what would her speed have to be?
Answers: 3
image
Physics, 22.06.2019 15:30, ayoismeisalex
What is a view of science and psychology that says the value of knowledge depends on its usefulness? a. pragmatism b. psychotherapy c. physiology
Answers: 2
image
Physics, 22.06.2019 18:30, kayleahrayne
Ablock of mass m slides on a horizontal frictionless table with an initial speed v0 . it then compresses a spring of force constant k and is brought to rest. the acceleration of gravity is 9.8 m/s2. how much is the spring compressed x from its natural length? 1) x = v0*sqrt(k/(mg)) 2) x=v0*sqrt(m/k) 3) x=v0*((mk)/g) 4) x=v0*sqrt(k/m) 5) x=v0*(m/kg) 6) x=v0*sqrt((mg)/k) 7) x=(v0)^2/(2g) 8) x=v0*(k/(mg)) 9) x=(v0)^2/(2m) 10) x=v0*((mg)/k)
Answers: 3
Do you know the correct answer?
A thin, hollow tube with cross-sectional area 2 cm2 and length 20 cm has a 22 g mass at the bottom....

Questions in other subjects:

Konu
Mathematics, 22.12.2020 20:50