A machine gun fires 60 bullets per minute, with a velocity of 700 m/s .If each bullet has a mass of 50 g .Find the power developed by the gun

2100 kg*m/s

Explanation:

The proper term for power in this case is to use the physics term "impuls" = p.

1. Find the "power" developed by the gun to fire just 1 bullet.

2. multiply by 60 to find the power produced by the gun per minute.

p = m * v

where

m = mass of the bullet = 50 g = 0.050 kg

v = velocity of the bullet = 700 m/s

p = 0.050 * 700

p = 35 kg*m/s

So the impuls for 1 bullet is 35 kg*m/s

The gun can fire 60 bullets per minute so it's fireing power must there fore be 60 * 35 = 2100 kg*m/s

prndulum needs thread, weight clock to time swings

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//