If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance. What is its vertical displacement (in m) after 10 s? (g = 10 m/s2)

Explanation:

Using the equation of motion S = ut + 1/2 gt²

S = the vertical displacement (in m)

u = initial velocity of the object (in m/s)

g = acceleration due to gravity (in m/s²)

t = time taken (in secs)

Given u = 0m/s, g = 10m/s² and t = 10s, substituting this value into the equation to get the vertical displacement w have;

S = 0+1/2 (10)(10)²

S = 1000/2

S = 500m

The vertical displacement after 10seconds is 500m

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explanation: