A portable x-ray unit has a step-up transformer. The 120 V input is transformed to the 100 kV output needed by the x-ray tube. The primary has 47 loops and draws a current of 16 A when in use. What is the current output of the secondary in milliAmpere

The number of loops in the primary winding of the transformer draws our attention to it like some kind of consciousness-magnet.  But if and when we start to actually THINK about this question, we notice a subtle bad smell, and we realize that the number of loops in the transformer is a total red herring, and we don't need to worry about it at all.

-- The electrical power coming out of the transformer is equal to the electrical power going into it.

-- Electrical power = (voltage) x (current)

-- Power going in = (120 V) x (16 A) = 1,920 watts

-- Power coming out = (100,000 V) x (current)

100,000v x current = 1,920 W

Current = 1,920 W / 100,000 V

Current = 0.0192 A

Current = 19.2 milliAmperes

Leave the red herring where we found it and let it rot.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz