An object is held 24.8 cm from a lens of focal length 16.0 cm. What is the magnification of the image? PLS HELP!

1.82

Explanation:

Given that the

Object distance U = 24.8 cm

Focal length f = 16.0 cm

Let us first calculate the image distance by using the formula

1/f = 1/u + 1/v

Substitute f and u into the formula

1/16 = 1/24.8 + 1/v

Make 1/v the subject of formula

1/v = 1/16 - 1/24.8

1/v = 0.0625 - 0.04032258

1/v = 0.022177419

Find the reciprocal of both sides

V = 45.09 cm

Magnification = image distance ÷ object distance

Magnification = 45.09/24.8

Magnification = 1.818

Therefore, magnification of the image is 1.82 approximately

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get