At a distance of 2.5 cm from a long straight current-carrying wire, the magnetic field has a value of 1.3 T. What would be the value of the magnetic field at a point that is twice as far from the wire, when the wire carries twice as much current

The magnetic field is  

Explanation:

From the question we are told that

   The distance from the wire is  d = 2.5 cm  =  0.25 m

    The magnetic field is B  =  1.3 T

Generally the magnetic field that is as a result of as current carrying conductor is mathematically represented as

so  

given that the distance and the current is doubled

=>      

Hence  

=>      

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2