Physics, 26.06.2020 15:01, karizm2010
A gun is fired with muzzle velocity 1114 feet per second at a target 4950 feet away. Find the minimum angle of elevation necessary to hit the target. Assume the initial height of the bullet is 0 feet, neglect air resistance, and give your answer in degrees.
Answers: 3
![\theta = \frac{sin ^{-1} [\frac{R * g }{ u^2} ]}{2}](/tpl/images/0694/3380/24ecf.png)
![\theta = \frac{sin ^{-1} [\frac{4950 * 32 }{ 1114^2} ]}{2}](/tpl/images/0694/3380/97ae6.png)
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A gun is fired with muzzle velocity 1114 feet per second at a target 4950 feet away. Find the minimu...
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