find the period of a simple pendulum of 1m length placed on earth and on moon g on moon =1.67m/s² g on earth=10m/s²

= 4.86 s

= 1.98 s

Explanation:

Given:

Length = l = 1 m

Acceleration due to gravity of moon = = 1.67 m/s²

Acceleration due to gravity of Earth = = 10 m/s²

Required:

Time period = T = ?

Formula:

T = 2π

Solution:

For moon

Putting the givens,

T = 2(3.14)

T = 6.3

T = 6.3 × 0.77

T = 4.86 sec

For Earth,

Putting the givens

T = 2π

T = 2(3.14)

T = 6.3 × 0.32

T = 1.98 sec

e) none of the above answers are correct

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.