Ax = 44.4 m and Ay = 25.1 m Find the direction of the vector.

29.5 degree

Explanation: Given that

Ax = 44.4 m and Ay = 25.1 m 

The direction of the vector will be

Tan Ø = Ay/Ax

Substitute Ay and Ax into the formula

Tan Ø = 25.1/44.4

Tan Ø = 0.5653

Ø = tan^-1(0.5653153)

Ø = 29.48 degree

Ø = 29.5 degree approximately.

Therefore, the direction of the vector is 29.4 degrees approximately.

v=ir = 3x15 =45 v

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west