Physics
Physics, 23.06.2020 22:01, mia3128

If a person of mass M simply moved forward with speed V, his kinetic energy would be 12MV2. However, in addition to possessing a forward motion, various parts of his body (such as the arms and legs) undergo rotation. Therefore, his total kinetic energy is the sum of the energy from his forward motion plus the rotational kinetic energy of his arms and legs. The purpose of this problem is to see how much this rotational motion contributes to the person's kinetic energy. Biomedical measurements show that the arms and hands together typically make up 13.0 % of a person's mass, while the legs and feet together account for 35.0 %. For a rough (but reasonable) calculation, we can model the arms and legs as thin uniform bars pivoting about the shoulder and hip, respectively. In a brisk walk, the arms and legs each move through an angle of about ±30∘ (a total of 60∘) from the vertical in approximately 1 second. We shall assume that they are held straight, rather than being bent, which is not quite true. Let us consider a 70.0-kg person walking at 6.00 m/s having arms 67.0 cm long and legs 94.0 cm long.

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If a person of mass M simply moved forward with speed V, his kinetic energy would be 12MV2. However,...

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