Physics, 23.06.2020 19:01, makayladurham19
The place you get your hair cut has two nearly parallel mirrors 6.50 mm apart. As you sit in the chair, your head is 2.00 mm from the nearer mirror. Looking toward this mirror, you first see your face and then, farther away, the back of your head. (The mirrors need to be slightly nonparallel for you to be able to see the back of your head, but you can treat them as parallel in this problem.) How far away does the back of your head appear to be
Answers: 2
Physics, 22.06.2019 14:30, Scourge927
Multiply or divide to make this english distance conversion. 174 inches = feet (14.5, 58, 2,088, 23)
Answers: 2
Physics, 22.06.2019 16:50, justkevin1231
Aresistor with an unknown resistance is connected in parallel to a 9 ω resistor. when both resistors are connected in parallel to an emf source of 21 v, the current through the unknown resistor is measured with an ammeter to be 4 a. what is the resistance of the unknown resistor? answer in units of ω.
Answers: 3
Physics, 22.06.2019 17:30, ciaotaylor
Aball thrown by ginger is moving upward through the air. diagram a shows a box with a downward arrow. diagram b shows a box with an upward arrow. diagram c shows a box with a downward and upward arrow equal in size. diagram d shows a box with a downward and upward arrow with the downward arrow larger in size. which force diagram represents the forces on the ball? you may neglect the effects of air resistance.
Answers: 3
Physics, 22.06.2019 18:30, kayleahrayne
Ablock of mass m slides on a horizontal frictionless table with an initial speed v0 . it then compresses a spring of force constant k and is brought to rest. the acceleration of gravity is 9.8 m/s2. how much is the spring compressed x from its natural length? 1) x = v0*sqrt(k/(mg)) 2) x=v0*sqrt(m/k) 3) x=v0*((mk)/g) 4) x=v0*sqrt(k/m) 5) x=v0*(m/kg) 6) x=v0*sqrt((mg)/k) 7) x=(v0)^2/(2g) 8) x=v0*(k/(mg)) 9) x=(v0)^2/(2m) 10) x=v0*((mg)/k)
Answers: 3
The place you get your hair cut has two nearly parallel mirrors 6.50 mm apart. As you sit in the cha...
Mathematics, 15.12.2020 23:30
Mathematics, 15.12.2020 23:30
Mathematics, 15.12.2020 23:30