A car of mass 1000kg is moving at a speed of 20m/s. It's brought to rest at a distance of 50m. Calculate the net force acting on the car.

-4000 N

Explanation:

1. First let's look at what we know.

Mass: 1000 kg

Initial velocity: 20 m/s

Final velocity: 0 m/s

Displacement: 50 m

2. Let's try and apply a Kinematics equation here.

Looking at what information we have, I would say that this is the best equation:

v=v + 2aΔx

3. Plug in the numbers.

0 = 400 + 2(a)(50)

0 = 400 + 100a

-400 = 100a

a = -4 m/s^2

4. Use ∑F=ma

∑F = (1000)(-4)

∑F = -4000 N

where are the vectors ?

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.