Work out the potential difference if 11,500J of energy are transferred by 50C of charge. Answer in amps

460V

Explanation:

The following data were obtained from the question:

Energy (E) = 11500J

Charge (Q) = 50C

Potential difference (V) =.?

The energy, E stored in a capacitor is related to the charge, Q and potential difference, V by the following equation

E = ½QV

With the above equation, we can easily calculate the potential difference as follow:

E = ½QV

11500 = ½ × 50 × V

11500 = 25 × V

Divide both side by 25

V = 11500/25

V = 460V.

Therefore, the potential difference is

460V.

this could be newton#'s law of cooling. the cooling curve is exponential