If the object represented by the FBD below has a mass of 2.0 kg, what is the acceleration of the object?

B

Explanation:

Let us first resolve the forces.

Horizontal, the vectorial resolution is equal to zero. Since the positive direction and negative direction vector are of same magnitude. Therefore, summation of horizontal forces Fh = 0

Vertical resolution, the sum of forces will be Fv = 30 - 35 = - 5 N

Resultant force F = sqrt( Fv^2 + Fh^2)

Substitutes Fv and Fh. We get

R = sqrt ( 25) = 5N

We are given that the mass M = 2kg

From Newton second law,

F = Ma

Where a = acceleration

Substitute F and M and make a the subject of formula

5 = 2a

a = 5/2 = 2.5 m/s^2

Therefore, acceleration a of the object is 2.5 m/s^2 down.

b) returns freshwater to the earth.

c) returns freshwater to the earth.c) occurs after condensation.

d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.

happy to

pls mark as brainliest.

massxgravity x heght=weightxheight= pe

4900=490xh

h=10