A 35.0-kg child swings in a swing supported by two chains, each 2.96 m long. The tension in each chain at the lowest point is 436 N. (a) Find the child's speed at the lowest point. Consider all the vertical components of force acting on the swing when it is at its lowest point and relate them to the acceleration of the swing at that instant. m/s (b) Find the force exerted by the seat on the child at the lowest point. (Ignore the mass of the seat.)

6.69m/s,529N

Explanation:

Now we have 3 forces acting on the boy at its least point, the two tensions on the string and its weight. The tensions are acting upwards why its weight is acting downwards.

Hence the net force causes the child to swing in a circular fashion without skidding off the swing.

This net force is the centripetal force.

The weight of the child is mass × g

35×9.8=343N

The net force = 436+436-343 = 529N

The centripetal force is defined mathematically as;

F = mass × velocity square/ length of string.

Hence 529 = 35V^2/2.96

V^2 = 529×2.96/35 =44.7383

V=√44.7383 =6.69m/s

B. The force exerted by the seat on the child is the net force which keeps the boy from falling.

529N

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

u

explanation: