The velocity of a particle moving along the x axis is given for 1> 0 by v: = (32.0t - 2.00t^3) m/s, where t is in s. What is the acceleration of the particle when (after t = 0) it achieves its maximum
displacement in the positive x direction?

The acceleration of the particle when it achieves its maximum displacement in the positive x-direction is 32 m/s²

To calculate the acceleration of the particle, we need to differentiate the expression for the velocity.

Given:

differentiate v with respect to t

When the particle achieves its maximum displacement,

Substitute these value of t into equation 1

Hence The acceleration of the particle when it achieves its maximum displacement in the positive x-direction is 32 m/s²

Learn more about acceleration here:

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

f=ma newton

f=100x2.5=250n