A 2.20 mH toroidal solenoid has an average radius of 7.00 cm and a cross-sectional area of 2.80 cm2 . You may want to review (Pages 994 - 997) . For related problem solving tips and strategies, you may want to view a Video Tutor Solution of Calculating self-inductance.
A. How many coils does it have? In calculating the flux, assume that B is uniform across a cross section, neglect the varation of B with a distance from the toroidal axis. B. At what rate must the current through it change so that a potential difference of 2.80 V is developed across its ends?enter the magnitude of the rate.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.

1 is a answer of a question