As part of an exercise program, a woman walks south at a speed of 2.00 m/s for 60.0 minutes. She then turns around and walks north a distance 3000 m in 25.0 minutes (a) What is the woman's average velocity during her entire motion?

The woman's average velocity during her entire motion is 2 m/s

Explanation:

Given;

initial speed of the woman, u =  2.00 m/s

initial time taken, t₁ = 60 minutes = 3600 seconds

initial displacement of the woman, x₁ = ?

final displacement of the woman, x₂ = 3000 m north

final time taken , t₂ = 25.0 minutes = 1500 seconds

The woman's average velocity during her entire motion:

initial displacement of the woman, x₁ = u x t₁  = 2.00 m/s x 3600 seconds

                                                                           = 7200 m South

Therefore, the woman's average velocity during her entire motion is 2 m/s

answer: ​ heat , electrical , nuclear ,

explanation:

not too sure thinking all accelerations are pointed down