Circuit A contains a battery, a switch, and a resistor connected in series. Circuit B contains a battery, a switch, an inductor, and a resistor connected in series. Initially, the switch is closed in both circuits. How does the behavior of the current in circuit B compare with that in circuit A as both switches are opened at the same time?
a. The current in circuit B decreases more slowly than that for circuit A since the inductor acts to maintain the current in the circuit.
b. The behavior of the current in the circuit depends on the inductance of the inductor. If the inductance is small, the current will decrease rapidly; and if the inductance is large, the current will increase for a short time before decreasing.
c. The current in circuit B decreases more quickly than that for circuit A since the inductor increases the current in the circuit as its stored energy is released.
d. The current in both circuits decreases at the same rate because inductors do not affect the current in a circuit.
Answers: 2
Physics, 21.06.2019 19:00, pinsonjon1129
Yardım edin lütfen uzun cevap lazım çok puan veriyorum
Answers: 1
Physics, 22.06.2019 04:00, dlatricewilcoxp0tsdw
Drag each item into the proper state of matter category.
Answers: 1
Physics, 22.06.2019 05:30, GreenHerbz206
Could someone . i have tried to solve myself but my calculation is off
Answers: 3
Circuit A contains a battery, a switch, and a resistor connected in series. Circuit B contains a bat...
Biology, 12.01.2020 00:31
Mathematics, 12.01.2020 00:31
Mathematics, 12.01.2020 00:31
Mathematics, 12.01.2020 00:31
Mathematics, 12.01.2020 00:31
Mathematics, 12.01.2020 00:31