Por una espira de 0.5 m2 de área circula una corriente de 5 A. Calcula la densi- dad de flujo magnético B considerando que la espira considera la permeabilidad del medio es la del aire

Explanation:

The density of the magnetic flux is given by the following formula:

The normal vector A and the vector of the magnitude of the magnetic field are perpendicular, then, the angle is zero:

The magnitude of the magnetic field is calculated by using the formula for B at a distance of x to a point in the plane of the loop:

For x = 0 you have:

R is the radius of the circular loop and its values is:

Then, you replace in the equation for B with mu_o = 4\pi*10^-7 T/A:

and the density of the magnetic flux is

it is very well related to a lot of things but with my limited knowledge i can confidently say that the answer is space.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards