Two speakers create identical 240 Hz sound waves. A person is 1.47 m from Speaker 1. What is the MINIMUM distance to Speaker 2 for there to be destructive interference at that spot? (Hint: v= lambda f=343 m/s) (Unit = m)

2.90 metres

Explanation:

Distance of speaker 2 =?

Distance of speaker 1 = 1.47m

Velocity = 343

f = 240Hz

For constructive interference to occur:

Difference in distance or path = wavelength

For minimum distance, n = 1

Distance 2 - distance 1 = nλ

Recall λ = v/f

V = Velocity ; f = frequency

Distance 2 - distance 1 = v/f

Distance 2 - 1.47 = (343/240)

Distance 2 = 1.429 + 1.47

Distance 2 = 2.899 meters

Minimum Distance of speaker 2 for their to be constructive interference = 2.90meters

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

h o h o hope you have a merry christmas!

snell's law

refractve index = sin incidence / sin refraction