A tuba creates a 4th Harmonic of frequency 116.5 Hz. When the first valve is pushed, it opens an extra bit of tubing 0.721m long. What is the new frequency of the 4th Harmonic? Hz

New frequency = 103.3Hz

Explanation:

Given that the

Frequency F = 116.5 Hz

The tube is an opened tube.

The relationship between wavelength and the length of the tube is

λ = 2L/n

Where

λ = wavelength

L = length of the tube

n = number of harmonic

For 4th harmonic,

λ = 2L/4 = L/2

But wave speed V = F(λ)

Substitutes (λ) into the wave speed formula

V = FL/2

Let's assume that the V is the speed of sound = 330m/s

Substitutes the V and F into the formula above.

330 = 116.5L/2

Cross multiply

660 = 116.5L

L = 660/116.5

L = 5.67 m

Given that the first valve is pushed, it opens an extra bit of tubing 0.721m long.

New length = 5.67 + 0.721 = 6.39 m

New frequency will be

330 = 6.39F/2

Cross multiply

660 = 6.39F

F = 660/6.39

F = 103.3 Hz

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form