An electron in a mercury atom jumps from level a to level g by absorbing a single
photon. Determine the energy of the photon in joules.

7.39ev

Explanation:

Energy levels are found inside the atom. Electrons occupy these energy levels depending on the energy they possess. Electrons can move from one energy level to another due to absorption or emission of a photon or other factors. As the electron, jumps from a higher energy level to a lower energy level emitting a photon of measurable frequency, the photon carries energy equal to the amount of energy between the gap of the levels. This idea was first proposed by Neils Bohr and became the forerunner of the wave mechanical model of the atom.

Hence the energy of a photon is the energy of the gap between the two energy levels. Since Ea= 2.48ev and Eg= 10.38 ev.

If an electron jumps from Ea to Eg, the energy of the photon absorbed is given by;

E=Eg-Ea

E= 10.38ev - 2.48ev

E= 7.39ev

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

the answer is 3.1 his answer is wrong mines is right