A particle starts with an initial velocity 3.5m/s and it accelerates uniformly at the rate 0.5m/s². The displacement in the first 3 seconds. *
pls help me

final speed is (3.5 + 1.5) = 5 m/s

Explanation:

If it accelerates for 3 seconds with 0.5m/s² What will be the new speed?

An acceptation of 0.5 m/s² means that every second the speed increases by 0.5 m/s. After 3 * seconds you gain in speed by 3 * 0.5 = 1.5 m/s So the final speed is 3.5 + 1.5 = 5 m/ s

Here is another method:

u =3.5m/s

Make use of

a = (v-u) / t

where:

a is acceleration in m/s² =0.5

v is final velocity in m/s = ?

u is initial velocity in m/s = 3.5

t is time in s = 3

Rewrite so it starts with v =

a = (v)/t - (u) / t

v/t = u/t + a

multiply left and right of the = sign by t

v = u + a * t

Substitutie the known numbers

v = 3.5 + 0.5 * 3

final speed is (3.5 + 1.5) = 5 m/s

c. magnitude and direction

80cm/s.

24cm/s.

53.3cm/s.