You attach a meter stick to an oak tree, such that the top of the meter stick is 2.87 meters above the ground. Later, an acorn falls from somewhere higher up in the tree. If the acorn takes 0.296 seconds to pass the length of the meter stick, how high ℎ0 above the ground was the acorn before it fell, assuming that the acorn did not run into any branches or leaves on the way down?

3.06 m

Explanation:

Given:

y₀ = h

y₁ = 2.87 m

y₂ = 1.87 m

v₀ = 0 m/s

a = -9.8 m/s²

t₂ − t₁ = 0.296 s

y₁ = y₀ + v₀ t₁ + ½ at₁²

2.87 = h − 4.9t₁²

y₂ = y₀ + v₀ t₂ + ½ at₂²

1.87 = h − 4.9t₂²

Subtracting the equations:

1 = (h − 4.9t₁²) − (h − 4.9t₂²)

1 = h − 4.9t₁² − h + 4.9t₂²

1 = 4.9 (t₂² − t₁²)

1 = 4.9 (t₂ − t₁) (t₂ + t₁)

1 = 4.9 (0.296) (0.296 + 2t₁)

t₁ = 0.197

Solve for h:

2.87 = h − 4.9 (0.197)²

h = 3.06

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

  the unit of the measure =

explanation:

  the property that is quantified by the energy needed per of material to raise the temperature by one.

  si unit of energy = joule (j)

  si unit of temperature = kelvin (k)

  si unit of mass of material = kilogram (kg)

the property that is quantified by the energy needed per of material to raise the temperature by one is called specific heat.

the unit of specific heat is