How many electrons must be removed from a neutral, isolated conducting sphere to give it a positive charge of 8.0 x 10 8 C? [Q=ne]

Hence the number of electrons that must be removed from the given sphere is,

Given-

In the problem there is a sphere with a neutral charge.

This means the charge on the sphere = 0C

We know that negative charge on an electron is,

to make this neutral charge sphere to the positive charge of

we need to divide this positive charge with the charge of one electron

Now the number of electrons X with a negative charge will be equal to,

Hence, the number of electrons that must be removed from the given sphere is,

For more about the charge of electrons follow the link,

link

the ball will have a charge of 8x10^8C when we remove 5x10^27 electrons.

Explanation:

If the sphere is neutral, then the charge of the sphere is 0C

Now, when we remove an electron (-1.6*10^-19 C) we are subtracting a negative number, so the new charge of the sphere is: 1.6*10^-19 C

Now, for N removed electrons, the charge of the sphere is:

N*1.6*10^-19 C

We want to find the number N when:

N*1.6*10^-19 C = 8.0x 10^8 C

N = (8.0/1.6)x10^(8 + 19) = 5x10^27 electrons.

answer; ///i do believe that the correct answer is ; ///(physical change);