Una persona realiza los siguientes desplazamientos sobre una línea recta: primero camina 52 metros a la derecha, después camina 31 metros hacia la izquierda, luego camina 48 metros hacia la derecha, nuevamente camina 55 metros hacia la izquierda, para finalmente caminar 22 metros hacia la derecha. Determinar: a) El desplazamiento de la persona b) El camino recorrido por la persona. c) La velocidad de la persona, si demora 12 segundos en describir esa trayectoria

a) d = 36 m   with direction to the right,

to the right

Explanation:

a) This exercise asks us to calculate the displacement that is a vector

            d = d₁ + d₂ + d₃ + d₄

let's assign the right shift as positive

         d₁ = 52 m

         d₂ = -31m

         d₃ = 48 m

         d₄ = -55 m

          d₅ = 22m

we substitute

           d = 52 -31 +48 -55 +22

           d = 36 m

with direction to the right

b) they ask to calculate the distance traveled, which is the magnitude of the distance traveled

          D = d₁ + d₂ + d₃ + d₄ + d₅

where the quantities are in absolute value, I mean positive

           D = 52 +31 48 +55 +22

           D = 208 m

c) the average speed that is the displacement between the time it takes in this magnitude

         v = d /t

         v = 36/10

         v = 3.6 m / s

to the right

it is given that trillions of microbes make up to 1% to 3% of the body mass.

let's take average of this percentage: 2%

consider the average mass of the human body as 70 kg.

then, trillions of microbes would have mass  

therefore, 100 trillion micro-organisms would weigh:

this is an approximate value and could change depending on the mass of the human body and percentage of the microbes present in it.

average mass per microorganism =

the answer is 100. i just did this lesson and got a 100% on it. : )

-fishtank