A boy of mass m is standing on the edge of a merry-go-round platform, which is initially rotating with a constant rotational velocity ωi (initial state). The rotational inertia of the merry-go-round is I, and the radius of the platform is r. After the boy steps down from the platform, tangentially to its edge, the merry-go-round continues rotating with a smaller rotational velocity ωf, and the boy continues moving away from the platform with constant speed v (final state).
Derive the expression for ωf in terms of the relevant quantities. Express your answer in terms of I, m, r, v, and ωi.

The speed was not exceeded so it was slow

Answertraveling around a circular trackexplanation"traveling around a circular track" is the best answer as you could be traveling around a circular track at a constant speed. your velocity would therefore have the same magnitude but will always be constantly direction. since acceleration is the rate of change of velocity, the rate of change will only involve the direction of velocity and not the magnitude.wrong choices: "an object at rest" does not accelerate at all"increasing speed while traveling around a curve" means that the acceleration will not be constant due to only change in direction; it will be constant due to both magnitude and direction"an object in free fall" does not necessarily change direction 

Ithink it’s: light bounce if off a mirror