A 400 kg bear is motionless on a 30 degree angle hill. What is the force acting on the bear? What is the x component? What is the y component? What is the normal force? What is the friction force?

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i already answered it by 34/s

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j