Quiz3: Identical 2.0 µC charges are located on the vertices of a square with sides that are 2.0 m in length. Determine the infinity) at the center of the square. electric potential (relative to zero at

V = 50.91 kV  

Explanation:

given data

charges = 2.0 µC  =  2.0 ×  C

length of a =2.0 m

solution

we get here first distance by corner to center that is express as

r = a ÷ √2     ...............1

put here value and we get

r = 2.0 ÷ √2

r = √2 m

and

here potential at distance r due the point charge (q) is express as

V = q ÷ ( 4 π εo r  )     ...............2

so 4 charges the total potential will be as

V = 4q ÷ ( 4 π εo r  )    ...............3

and here 1 ÷ (4 π εo ) = 9.0 × N m²/C²

so that

total potential at the center will be

V = ( 4 ×  9.0 ×  × 2.0 × )  ÷ √2

solve it and we will get

V = 50.91 kV  

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hope this ! : )

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.