A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.59 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 2190 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 3.91 V/m, (b) in the negative z direction and has a magnitude of 3.91 V/m, and (c) in the positive x direction and has a magnitude of 3.91 V/m?

a) 1.88*10^-18 N

b) 6.32*10^-19 N

c) 1.9*10^-18 N

Explanation:

The total force over the electron is given by:

the first term is the electric force and the second one is the magnetic force.

You have that the velocity of the electron and the magnetic field are:

by using the relation  j X (-i) =- j X i = -(-k) = k, you obtain:

a) For an electric field of 3.91V/m in +z direction:

b) E=3.91V/m in -z direction:

c) E=3.91 V/m in +x direction:

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.