In a double‑slit interference experiment, the wavelength is λ = 452 nm λ=452 nm , the slit separation is d = 0.190 mm d=0.190 mm , and the screen is D = 49.0 cm D=49.0 cm away from the slits. What is the linear distance Δ x Δx between the eighth order maximum and the third order maximum on the screen?

Δx = 5.82mm

Explanation:

To find the distance between the eight maximum and the third one you use the following formula:

  (1)

λ: wavelength = 452*10^-9 m

m: order of the fringes

D: distance to the scree = 0.49m

d: distance between slits = 0.190*10^-3 m

you use for m=8 and m=3, then you calculate x8 - x3:

hence, the distance between these fringes is 5.82mm

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