We are going to make an imaginary engine using water. We are going to heat 100≤ grams of water to 120 C from its initial temperature of 22 C. This would be the heat extracted from the hot reservoir. Then the steam will condense back into water and will be at a temperature of 30 C. This would be the exhaust expelled into the cold reservoir. You can assume the mass of the water and the mass of the steam is the same in this case. How much work can be done using this engine? The specific heat of water is 1 cal/(g C), the specific heat of steam is 0.48 cal/(g C), and the latent heat of vaporization

c because the action was the roller coaster reaches bottom of hill (action) reaction would be blood tends to drain away from head

hope this !

talk back to him about the sport and show him your expertise or leave the room

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.