An object is moving at a velocity of 30m/s. It accelerations to a velocity of 55m/s over a time of 12.5 m/s. What acceleration did it experience?

Acceleration = (change of speed) / (time for the change)

Change of speed = (speed at the end) - (speed at the beginning)

Change of speed = (55 m/s) - (30 m/s)

Change of speed = 25 m/s

Acceleration = (25 m/s) / (12.5 seconds)

Acceleration = 2 m/s²

2m/s^2

Explanation:

Initial velocity(u)=30m/s

Final velocity(v)=55m/s

Time(t)=12.5s

Acceleration=?

Acceleration=(v-u)/t

Acceleration=(55-30)/12.5

Acceleration=25/12.5

Acceleration=2m/s^2

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

there are no atoms