A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction, and a magnetic field of magnitude 1.15 T points in the positive direction. If the net force acting on the particle is 6.13E-3 N in the positive direction, calculate the magnitude of the particle's velocity. Assume the particle's velocity is in the - plane.

Explanation:

Using:

Force = electric field * charge

Force = magnitude of charge * velocity * magnetic field * sin tither

Force on particle due to electric field:

Force on particle due to magnetic field:

is in the positive x direction as is in the negative x direction while net force is in the positive x direction.

Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.