Two particles of masses m1m1m_1 and m2m2m_2 (m1

the correct answer is: more than 5 meters of particular m1, but less than 10 m of the particle m₂

Explanation:

The center of mass, the point of a system where all external forces can be applied, is defined by

        = 1 /M ∑

where M is the total mass of the system, x_{i} m_{i} are the position and mass of each item in the system,

let's apply this equation to our case

the total mass is

    M = m₁ + m₂

for the calculations we must fix a reference system, we will place it in the second mass (m₂)

     x_{cm}= 1/M (m₁ d + m₂ 0)

where d is the distance between the two masses in this case d = 10 m

    x_{cm} = m₁ / (m₁ + m₂) d

    x_{cm} = m₁ / (m₁ + m₂) 10

as the mass m₁ <m₂

Let us analyze the answer if the masses sides were equal the center of mass would be x_{cm} = 5 m, but since m₁ <m₂ the center of mass must be closer to m₂.

Therefore the correct answer is: more than 5 meters of particular m1, but less than 10 m of the particle m₂

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force