A 5.2nC charge exerts a repulsive force of 30mN on a second charge which is located at a distance of 60m away from it. what is the charge (magnitude and sign) of the second charge?

Charge,

Explanation:

It is given that,

Charge 1,

Repulsive force,

Distance between two charges, d = 60 m

We need to find the magnitude of second charge. The electric force between two charge is given by :

is second charge

k is electrostatic constant

So, the magnitude of second charge is 2.3 C. Hence, this is the required solution.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.