1. A 2 C charge moving at 15 m/s enters into a magnetic field of strength 8

T. What is the maximum force experienced by this charge? *

Maximum force on the charge is 240 N

Explanation:

We have given charge q = 2C

Speed of the charge v = 15 m/sec

Magnetic field B = 8 T

It is known that magnetic force on the moving charge is given by

Maximum force will be equal to

Therefore maximum force on the charge is 240 N

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

amplitude

hope this