A car is originally traveling at 15.0 m/s on a straight horizontal road. The driver applies the brakes, causing a car to decelerate uniformly at 4.00 m^2 until it comes to rest. Calculate the car's stopping distance.

28.13 m

Explanation:

Parameters given:

Initial speed of the car, u = 15 m/s

Acceleration of the car, a = -4 m/s ²

(The acceleration is negative because it is a deceleration)

We can find the distance traveled by the car by applying of the Newton's equations of motion:

v² = u² + 2 * a * s

Where v = final velocity of the car (0 m/s since the car comes to rest)

s = distance moved by the car

Therefore:

0² = 15² + (2 * -4 * s)

0 = 225 - 8s

=> s = 225/8

s = 28.13 m

The distance moved by the car before it comes to a stop is 28.13 m.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

magnets not strong enough

explanation: