Una máquina de tiro al plato lanza los mismos con un ángulo de 45° respecto al suelo y a una velocidad inicial de 100 km/h. ¿Qué altura máxima alcanzarán los platos? ¿Cuál será su alcance máximo?

Explanation:

A target shooting machine launches them at an angle of 45 ° to the ground and at an initial speed of 100 km / h. What maximum height will the dishes reach? What will be its maximum range?

Given that,

Then initial speed is 100km/hr

U = 100km/hr

U = 100×1000 / 3600

U = 27.78 m/s

And the angle of projection is 45°

θ = 45°

A. Maximum height?

The maximum height is given as

H = U²•Sin²θ / 2g

g = 9.81m/s²

Then,

H = 27.78² Sin²45 / 2 × 9.81

H = 27.78² × Sin45 × Sin45 / 19.62

H = 19.66 m

B. Maximum range R?

The range can be calculated using

R = U² Sin2θ / g

Rmax = U² / g

We can have maximum range when θ = 45°, and since θ is given to be 45°, then, we can use maximum range formula

R = U² / g

R = 27.78²/9.81

R = 78.65 m

The maximum range is 78.65m

Spanish

Dado que,

Entonces la velocidad inicial es de 100 km / h

U = 100 km / h

U = 100 × 1000/3600

U = 27.78 m / s

Y el ángulo de proyección es de 45 °

θ = 45 °

A. Altura máxima?

La altura máxima se da como

H = U² • Sin²θ / 2g

g = 9.81m / s²

Entonces,

H = 27.78² Sin²45 / 2 × 9.81

H = 27.78² × Sin45 × Sin45 / 19.62

H = 19.66 m

B. Rango máximo R?

El rango se puede calcular usando

R = U² Sin2θ / g

Rmáx = U² / g

Podemos tener un rango máximo cuando θ = 45 °, y dado que θ es 45 °, entonces, podemos usar la fórmula de rango máximo

R = U² / g

R = 27.78² / 9.81

R = 78.65 m

El alcance máximo es de 78.65 m.

this is poiselle's equation from fluid mechanic in physics. mech eng

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