You release a ball from a height of 1.5 feet. It bounces without losing any energy (whichmeans it will continue bouncing forever and the height of each bounce will be the same).Write an equation which models the height of the ball as a function of time assuming yourelease it at timet= 0 and it takes 2 seconds to strike the ground after you drop it.

Explanation:

Here, we have the equation of motion of the ball is given s follows

h = 0.5·g·t²

Whereby

U = The potential energy = 0.5·k·x² = 0.5·k·A²cos²(ωt )

K = The kinetic energy = 0.5·m·v² = 0.5mω²A²sin²(ωt)

The kinetic energy = 0.5·k·A²cos²(ωt ) as k = mω²

Therefore, the total mechanical energy, E of the ball = K + U

The total mechanical energy, E of the ball =0.5·k·A²(cos²(ωt) +  sin²(ωt))

∴ The total mechanical energy, E of the ball = 0.5·k·h² such that the height h is given by the following equation

A =

Where h =A·sin(ωt + ∅) = .

like poles repel so keep pushing north to north and repels funny to see this

answer; equivalent to a one(1) horsepower motor;