A fish lies 42 cm below the surface of a clear pond. If the index of refraction of water is assumed to be 1.33 and that of air is approximately 1, how far below the surface does the fish appear to a person looking down from above

Apparent depth = 31.58 cm

Explanation:

given data

fish lies below the surface D = 42 cm  

index of refraction n = 1.33

solution

we get here Apparent depth that is express as

index of refraction = Actual depth ÷  Apparent depth   ..............1

put here value and we get Apparent depth

1.33 =  42 ÷ Apparent depth  

solve it we get

Apparent depth =    

Apparent depth = 31.58 cm