A train is traveling at 30.0 m/s relative to the ground in still air. The frequency of the note emitted by the train whistle is 262 Hz. The speed of sound in air should be taken as 344 m/s. Part A What frequency fapproach is heard by a passenger on a train moving at a speed of 18.0 m/s relative to the ground in a direction opposite to the first train and approaching it

Explanation:

vs=speed of source=30 m/s

vl=speed of listener=18 m/s

actual frequency = f= 262 Hz

v = speed of sound = 344 m/s

apparent frequency = f' =?

a) f' = (v+vl /v- vs) f

= (344+18/ 344-30) x 262

= (362/314)x262

= 302 Hz

b) f' = (v-vl /v+vs) f

= (344-18/ 344+30) x 262

= (326/374)x262

= 228.3 Hz

= 302 Hz

answer: strength i guess

explanation:

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.