Physics, 23.04.2020 20:27, kemzzoo9338

In an earlier chapter you calculated the stiffness of the interatomic "spring" (chemical bond) between atoms in a block of aluminum to be 16 N/m. Since in our model each atom is connected to two springs, each half the length of the interatomic bond, the effective "interatomic spring stiffness" for an oscillator is 4*16 N/m = 64 N/m. The mass of one mole of aluminum is 27 grams (0.027 kilograms).

What is the energy, in joules, of one quantum of energy for an atomic oscillator in a block of lead?

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In an earlier chapter you calculated the stiffness of the interatomic "spring" (chemical bond) betwe...